A work in progress inspired by Ramanujan
This is the case a=13 of 2F1(a,a;a+12;−u)=2aΓ(a+12)√πΓ(a)∫∞0dx(1+2u+coshx)a
1481/4K(k3)∫10dx√1−x3√x2+27x3=2F1(13,13;56;−27)=47
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