j60A(τ)=j60E(τ)+1j60E(τ)=√j30B(2τ)j60B(τ)=(d2d6d10d30)2d1d3d4d5d12d15d20d60j60C(τ)=ab=1a(d6d10)3+1=ab2(d2d30)3−1j60D(τ)=(d1d12d15d20d3d4d5d60)=(d2d6d10d30d3d4d5d60)−1j60E(τ)=d4d6d20d30d2d10d12d60=√j30D(2τ)j60F(τ)=(d12d30d6d60)
where
a=d2d3d5d12d20d30b=d1d4d6d10d15d60
There are no linear relations between these functions.
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