Level 18

Level 18 has a second triple but it does not include purely moonshine functions. Define $d_k=\eta(k\tau)$ with the Dedekind eta function $\eta(\tau)$. Then 

$$\begin{align}\left(\frac{d_1\,d_6^4\,d_9}{d_2^2\,d_3^2\,d_{18}^2}\right)^2-1 &=  \left(\frac{d_1^3\,d_6^2\, d_9^3}{d_2^3\,d_3^2 d_{18}^3}\right)\quad\\ \left(\frac{d_1\,d_6^4\,d_9}{d_2^2\,d_3^2\,d_{18}^2}\right)^2+3 &=\left(\frac{d_3^6}{d_1\,d_2\,d_6^2\,d_9\,d_{18}}\right)\end{align}$$ Expressed as the triple of eta quotients $(a,b,c)$ such that $$a-1 =b\\ a+3=c$$ so $(m,n)=(-1,3)$. Then 

$$\begin{align}\frac{ab}{c} &= \left(\frac{d_1\, d_6^2\, d_9}{d_2\, d_3^2\, d_{18}}\right)^6\\ \frac{bc}{a} &= \left(\frac{d_3}{d_6}\right)^8\\ \frac{ac}{b} &= \left(\frac{d_3^2\, d_6^2}{d_1\, d_2\, d_9\, d_{18}}\right)^{2}\end{align}$$ where $(a,b,c)$ are the McKay-Thompson series of class 18C (A215412). They obey $$\left(\frac{16a}{bc}+\frac{bc}a\right)+2a  = \frac{ab}c+ \frac{bc}a+ \frac{ac}{b}$$ but $\dfrac{ab}{c}$ is a non-monster function with expansion (A128512).