Level 36, part 1

$$\begin{align}
j_{36A}(\tau) &= \left(\frac{d_2\,d_3^2\,d_{12}^2\, d_{18}}{d_1\,  d_4\,d_6^2\, d_9\, d_{36}}\right)^2\\
&=j_{36B}(\tau)+\frac{3}{j_{36B}(\tau)}+3\\
j_{36B}(\tau) &=\left(\frac{d_1\, d_4\, d_{18}}{d_2\,  d_9\, d_{36}}\right)\\
j_{36C}(\tau) &=  \left(\frac{d_6^2\, d_{12}^2}{d_2\,  d_4\,d_{18}\, d_{36}}\right) = \sqrt{j_{18B}(2\tau)}\\
j_{36D}(\tau) &= \left(\frac{d_4\, d_{9}}{d_1\,  d_{36}}\right)
\end{align}$$
There is no linear relation between these functions.