Entry 39 Using the Jacobi and Borwein theta functions

Let $\color{red}{q = e^{2\pi i\tau}}$. Given $\tau = \sqrt{-n}$ or $\tau = \frac{1+\sqrt{-n}}{2}$, then the solutions $\alpha, \beta,\gamma$ to the following equations,
$$\frac{_2F_1\big(\tfrac12,\tfrac12;1;\,1-\alpha\big)}{_2F_1\big(\tfrac12,\tfrac12;1;\,\alpha\big)}\,i=\color{red}{\sqrt{4}\,\tau}$$ $$\frac{_2F_1\big(\tfrac13,\tfrac23;1;\,1-\beta\big)}{_2F_1\big(\tfrac13,\tfrac23;1;\,\beta\big)}\,i=\color{red}{\sqrt{3}\,\tau}$$ $$\frac{_2F_1\big(\tfrac14,\tfrac34;1;\,1-\gamma\big)}{_2F_1\big(\tfrac14,\tfrac34;1;\,\gamma\big)}\,i=\color{red}{\sqrt{2}\,\tau}$$ are given by, $$\;\alpha =\frac{16}{u_1^8+16} = \left(\frac{\sqrt2 }{u_2}\right)^8  = \left(\frac{\vartheta_2(q)}{\vartheta_3(q)}\right)^4$$ $$\beta = \frac{27}{v_1^{12}+27} = \left(\frac{3}{v_2^3+3}\right)^3 = \left(\frac{c(q)}{a(q)}\right)^3$$ $$\gamma = \frac{64}{w_1^{24}+64} = \left(\frac{8}{w_2^8+8}\right)^2 = \left(\frac{f(q)}{d(q)}\right)^2$$ where, $$\quad u_1 = \frac{\eta(\tau)}{\eta(4\tau)},\quad u_2 = \frac{\eta^3(2\tau)}{\eta(\tau)\,\eta^2(4\tau)}$$ $$v_1 = \frac{\eta(\tau)}{\eta(3\tau)},\quad v_2 = \frac{\eta(\tau/3)}{\eta(3\tau)}$$ $$w_1 = \frac{\eta(\tau)}{\eta(2\tau)},\quad w_2 = \frac{\eta(\tau/2)}{\eta(2\tau)}$$ and where the functions of $\color{red}{q = e^{2\pi i\tau}}$ are the Jacobi and Borwein theta functions discussed in Entry 38. Also, $\alpha= \lambda(2\tau)$ with the modular lambda function $\lambda(\tau)$.